www.5129.net > python中如何让二维数组中的每个元素减去它的均值?

python中如何让二维数组中的每个元素减去它的均值?

a=[1,4,8,10,12] b=len(a) sum=0 print ("数组长度为%s" % b)for i in a: sum=sum+i print ("均值为:%s" % sum/b)

def average(array): avg = 0.0 n = len(array) for num in array: avg+= 1.0*num/n return avg具体如下: 1、简介 Python(英语发音:/ˈpaɪθən/), 是一种面向对象、解释型计算机程序设计语言,由Guido van Rossum于1989年底发明,...

# many solutions for it, here is one.def avg(x): global size return x / size * 1.seq = [i for i in xrange(120)]size = 12for slist in [seq[i:i+size] for i in range(0, len(seq), size)]: print map(avg, [reduce(lambda x, y: x+y, sl...

a=[] b=[] def sum_file(l): return sum(float(l)) / len(l) c=raw_input('aaa:') for i in c.split(): if int(i) % 2 == 0: a.append(int(i)) else: b.append(int(i)) print "Even the average:",sum_file(a) print "Average of the odd-number...

def isplit_by_n(ls, n): for i in range(0, len(ls), n): yield ls[i:i+n]def split_by_n(ls, n): return list(isplit_by_n(ls, n))

>>> l=[1, 2, 3, 4, 5, 4,3,2,1] #输入数字到数组中>>> sum(l)/len(l) #求平均数2.7777777777777777>>> "{:.3f}".format(sum(l)/len(l)) #求平均数,保留3位小数'2.778'

# many solutions for it, here is one. def avg(x): global size return x / size * 1. seq = [i for i in xrange(120)] size = 12 for slist in [seq[i:i+size] for i in range(0, len(seq), size)]: print map(avg, [reduce(lambda x, y: x+y...

a = list(range(1008))b = [sum(a[i:i+12])/12 for i in range(0,len(a),12)]

sum(n1,n2,n3,...,nn)/n round函数用来确定小数位数 如果你只想要小数部分: sum(n1,n2,n3,...,nn)/n-sum(n1,n2,n3,...,nn)//n //为整除符号 1.如果你是要返回一定位小数的结果: >>> def average(bits,*args): from numbers import Number for ...

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