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lg25+lg2*lg50+^2怎么计算

等于2

百度 lg25+lg2*lg50+(lg2)^2怎么计算,要有过程,谢谢 2011-11-11 | 分享 数学难题,学霸帮你立即下载 满意回答 =lg5+lg2*(lg5+lg10)+(lg2) =2lg5+lg2*lg5+lg2+(lg2) =2lg5+lg2(lg5+lg2)+lg2 =2lg5+lg2+lg2 =2(lg5+lg2) =2 我不是他舅 | 2011-11...

lg2)²+lg2*lg50+lg25=(lg2)²+lg2(1+lg5)+2lg5=lg2(lg2+lg5+1)+2lg5=2lg+2lg5=2 祝学习进步哈!

2lg2 + lg25 = 2lg2 + lg5² = 2lg2 + 2lg5 = 2(lg2 + lg5) = 2lg10 = 2

写成式子: lg2×lg2+lg50×lg4+lg4+lg5×lg5+lg25 =lg2×lg2+lg(2×5^2)×lg(2^2)+lg(2^2)+lg5×lg5+lg(5^2) 由lg(a*b)=lga+lgb,lg(a^b)=blga得到 =lg2×lg2+(lg2+2lg5)×2lg2+2lg2+lg5×lg5+2lg5 =lg2*lg2+2lg2*lg2+4lg2*lg5+2lg2+lg5*lg5+2lg5 =3(lg2...

(lg2) +lg2·lg50+lg25= =(lg2) +lg2·(1+lg5)+2lg5 =(lg2) +lg2lg5+lg2+2lg5 =lg2(lg2+lg5)+lg2+2lg5 =lg2*lg10+lg2+2lg5 =lg2+lg2+2lg5 =2(lg2+lg5) =2lg10 =2

=lg2(lg2+lg50)+lg25 =2lg2+lg25 =2

由题,lg5lg20-lg2lg50-lg25=lg5(2lg2+lg5)-lg2(2lg5+lg2)-2lg5=lg25-lg22-2lg5=lg5-lg2-2lg5=-(lg2+lg5)=-1故答案为-1

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