www.5129.net > 已知三角形ABC中,角ABC所对的边分别为ABC,且A%C/A+B=sinA%sinB/sin(A+...

已知三角形ABC中,角ABC所对的边分别为ABC,且A%C/A+B=sinA%sinB/sin(A+...

⑴sin(A+B)=sin(180° -C)=sinC, 由正弦定理得:(a-c)/(a+b)=(

⑴sin(A+B)=sin(180° -C)=sinC, 由正弦定理得:(a-c)/(a+b)=(

(a-c)/(b-c)=sinB/(sinA+sinC) (a-c)(sinA+sinC)=(b-

由正弦定理得sinA+(√2/2)sinC=sinBsin(A+π/4) sinA+(√2/2)s

A+C=2*B; //等差数列 A+B+C=180; //内角和 3*B=180,

2asin(C+π/6) = b+c 根据正弦定理有: 2sinAsin(C+π/6) = si

已知(a-b)(sinA+sinB)=(c-b)sinC 由正弦定理有:a/sinA=b/sinB

(1) asin2B=√3bsinA sinA2sinBcosB=√3sinBsinA A、

1.∵A、B、C是三角形的三个内角 ∴sinB≠0,A+B+C=180° ∵a=b,则A=B ∴C=

根据正弦定理: a/sinA=b/sinB=c/sinC=k (a+c)/b=(sinA-sin

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